need help!!
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need help!!
Guest Wed Nov 09, 2011 9:27 pm
A 10 ft tall flagpole stands next to a tree. The shadow of the flagpole is 17 ft and the shadow of the tree is 50 ft. What is the height of the tree? Round to the nearest tenth if necessary.
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Re: need help!!
That-Awkward-Kid Fri Nov 11, 2011 4:32 pm
I do not understand the first one. The second one is cut off. As for the third one:
If 10 feet=17 shadow feet then to find the tree you need to pick a variable (i chose x) to represent the height of the tree. So x=50. Since 10=17 then for every seventeen feet of the fifty there is ten feet of tree. You divide 50 by seventeen to get 2.9. Then because there is roughly 2.9 seventeens in fifty and one seventeen is equal to ten, you multiply ten by 2.9 to get 29. So the tree is twenty nine feet tall, approximately. To check your work you can do: 29=50 and 10=17. If 10=17, then 20=34 and 9=15.3 (to find this you would do 17 times .9 because 9 is 90% of ten and 90%=.9) then 20+9=29 and 34+15.3=49.3 which is approximately fifty. (just round to fifty because we rounded our decimal before to find 2.9 in the first place so its okay that this answer isnt 100% accurate)
Hope that helps :)
If 10 feet=17 shadow feet then to find the tree you need to pick a variable (i chose x) to represent the height of the tree. So x=50. Since 10=17 then for every seventeen feet of the fifty there is ten feet of tree. You divide 50 by seventeen to get 2.9. Then because there is roughly 2.9 seventeens in fifty and one seventeen is equal to ten, you multiply ten by 2.9 to get 29. So the tree is twenty nine feet tall, approximately. To check your work you can do: 29=50 and 10=17. If 10=17, then 20=34 and 9=15.3 (to find this you would do 17 times .9 because 9 is 90% of ten and 90%=.9) then 20+9=29 and 34+15.3=49.3 which is approximately fifty. (just round to fifty because we rounded our decimal before to find 2.9 in the first place so its okay that this answer isnt 100% accurate)
Hope that helps :)
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re: i need help
Guest Sat Nov 19, 2011 11:28 pm
Solve the equation.
10t – 5 = 60
http://www.pearsonsuccessnet.com/temp-images/testitems/741780/itemimages/TT_PH_EN_MA_A1_2011_02_0041_1.png
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Re: need help!!
Guest Sun Nov 20, 2011 5:30 pm
In the process of solving an equation, a student noticed that only integers remained on each side of the equation. The student concluded that the equation must have no solution. Is the student correct? Explain.
A. The student is correct. When variables are eliminated from an equation, the equation must have no solution.
B. The student is incorrect. When variables are eliminated from an equation, the equation must be an identity and therefore has infinitely many solutions.
C. The student is correct. When variables are eliminated from an equation, the equation must be an identity and therefore has infinitely many solutions.
D. The student is not necessarily correct. The integers on each side of the equation could be equal, so the equat
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Re: need help!!
Supa-Bacon-Cat Fri Jan 20, 2012 11:54 pm
*~Shiny Umbreon ~* wrote:x + 8 = 4
For this one you would subtract 8 from the 4 and you would get x=-4
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